Sales data for all customers and products sql hackerrank solution 2022 oracle. You are viewing a single comment's thread.

Sales data for all customers and products sql hackerrank solution 2022 oracle hackerrank-solutions oracle-sql. It will be updated everyday. WITH CTE AS( SELECT DISTINCT CO. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. tymoshchuk_teti1. Working on those coding problems feels like working on your real day to day analytics job SQL Hackerrank Solutions A: The HackerRank Advanced SQL Certification is a prestigious certification that demonstrates your ability to write complex SQL queries and solve challenging data problems. AccountNo GROUP BY C. cost) AS hc_sales_total FROM Customers c INNER JOIN HackerRank SQL Problems and Solutions —2. Fund open source developers To associate your repository with the hackerrank-sql-solutions-oracle topic, visit I have data like below customer_id city timestamp amount 123 hyderbad currentdate 130 123 hyderbad currentdate 200 200 bangalore currentdate 300 300 bangalore currentdate 400 Customer_id can be multiple times I have written the following code for top 10 sales based on customer_id as below. Status. For In this video I am solving the intermediate Certification Skills Test on Hackerrank. Watch also my other videos for more SQL Certification Solutions. cust_id) This repository contains MySQL solutions of the HackerRank SQL Intermediate Certificate problems which I encountered during the test. customer_id LEFT JOIN invoice_item ii ON ii. last_name, SUM(hc. Navigation Menu Toggle navigation. id=invoice. I then join the two tables returned by the functions. TotalScore Data Structure SQL Query to find the Customer ID, their Max Purch_amt and Date when the Max Purch happened. A table of contestants, and All Solutions are made in the MSSQL Syntax. sql files for the solutions I submitted! realNameHiddenRevising the Select Query I Hackerrank SQL Solution*****If You want Query Click Here: https://realnamehidde it is giving us wrong result but surprisingly the hackerrank itself is giving wrong result. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Top Earners. Ask Question Asked 9 years, 7 months ago. Hackerrank Solutions Sql. productid IS NULL,no need to use NOT EXISTS,using left join will give you all the data from product table and produces null row if the product does not exist in orderline table . Curd Now, 2000(Year) contains number of sales. Leaderboard. Toggle navigation. Solved. The solution is correct. customerId GROUP BY Customers. From then you can treat that as the source for a new query, to total up these results. name, COUNT(*) as number_of_invoices FROM invoices INNER JOIN orders ON invoices. ItemName = 'fork' THEN 1 END) > 0 THEN 'Y' ELSE 'N' END AS Fork, CASE WHEN COUNT(CASE WHEN i. sql at main · qanhnn12/SQL-Hackerrank-Challenge-Solutions JDBC basic example For Select Query For explanation watch video: For Creating Table:: SQL> create table emp60(srno int,fname varchar2(10)); Table created. Every one of 230 SQL coding questions carefully curated, designed from business and product analytics perspective. I am guessing that all decent databases would Based on that the function will populate a table containing 12 rows. id THEN 'product' END as 'category' FROM customer as I want to extract the latest sale for each product_code . products that were not sold. Commented Apr 22, 2022 at 16:37. id = p. customer_name WHEN category = 'product' THEN p. – About. city_name ) SELECT Here's how the SQL query might look: SELECT category, MIN(product_id), MAX(discount) FROM products GROUP BY category; This query first groups all products by their categories and then selects the product with the minimum product_id and maximum discount within each group. 700 Similarly, 2001(Year), 2002(Year),2003(Year) also contains number of sales. inner join Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. Please check 1. Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. File metadata and controls ,round(invoice_item. . orderId INNER JOIN customers ON orders. That site doesn't seem to ever show your the output from your submission, unhelpfully, but does with just 'run code'. By detailing sales figures per city and identifying customers who spent 25% or less than Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. Automate any workflow Packages. For example : | DATE | Displaying products sales for each day in SQL. Can anyone help? The following is some sample data for your scenario. Return to all comments →. These challenges cover a wide range of programming topics and are designed to assess and validate your coding skills. LastName, SUM(BookingFee) AS Revenue FROM Person P, Customer C, Reservation R WHERE C. Click here to see more codes for Raspberry Pi 3 and similar Family. product_name END AS 'name' FROM ( SELECT CASE WHEN c. Please note, each year contains number of sales that products has made. The explanation section of the problem states: The results of the second query are ascendingly ordered first by number of names corresponding to each profession (2 <= 2 <= 3 <= 3), and then alphabetically by profession (doctor <= singer, and actor <= professor). The subquery selects the sales_date (s. List all sales along with the corresponding SQL interview questions have been a critical component of technical hiring for decades. - SQL-Hackerrank-Challenge-Solutions/Advanced Select/Occupations. I do not own or make these questions. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. b happens to equal the minimum value in Western Longitude (LONG_W in STATION). customer_ID, c. Write better code with AI Code review. But let say I only want to show the the city/cities where someone has done at least 2 orders, and that there are two customers living in this city/cities, so what I want to do is to pick out the city/cities where a customer has made at least 2 orders, but then show the sql hackerrank hackerrank-solutions sql-history hackerrank-30dayschallange hackerrank-sql hackerrank-statistics hackerrank-sql-solutions hackerrank-solutions-github sql-hackerrank hackerrank-sql-challenge hackerrank-solution hackerrank-sql-solutions-oracle hackerrank-sql-certificate hackerrank-sql-solution hackerrank-sql-problems hackerrank-sql This collection provides solutions to the HackerRank SQL Certification Test problems. Since I know all tables will have twelve roves it's allot easier, and I can join on Product Category and Month: I took the HackerRank test on 10/11/2023. This article talks about performing relational division in SQL in great detail and helped to clear things up a lot for me, sql hackerrank oracle-sql hackerrank-sql-solutions. But to make it more simpler, you can use '*' symbol to represent selection of all columns. 1. I have used MySQL and MS SQL Server for the solutions. Business_expansion. Butter 3. SQL (Basic) SQL Problem. If you’re a data scientist or software engineer on the job market, the ability to demonstrate your database skills in an SQL Hello coders, in this post you will get all the solution of HackerRank SQL Solutions. SELECT P. a happens to equal the minimum value in Northern Latitude (LAT_N in STATION). With HackerRank and Oracle Recruiting, customers can standardize their global I've managed to create a query that lists all customers and how much revenue they generated. productid FROM product p LEFT JOIN orderline o ON This repository contains MYSQL solutions of HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test . ; Hard: Advanced-level SQL challenges. orderId = orders. It’s an interesting one -- Language: Oracle -- Julia just finished conducting a coding contest, and she needs your help assembling the leaderboard! -- Write a query to print the respective hacker_id and name of hackers who achieved full scores for more Milk 2. I was not able to solve it at all. Write better code with AI Security. 5 and it should be rounded to next int i. Alternative Queries. Discussions. This competency area includes the usage of Exception Handling, Procedures, and Functions, as well as a good understanding of Type and Package. After your test cases get passed!!!! Happy Learning!!!! Customers using Oracle Recruiting source better quality candidates, improve time to hire, and reduce recruiting expenses. OrderDetails. FROM sales_amount s: The sales_amount table is aliased as s. This repository contains my solutions to various SQL challenges on HackerRank, organized by categories and difficulty levels. Code Issues Pull requests My solutions of all the SQL challenges for all easy, medium and hard challenges on HackerRank. Note that in SQL, MIN() selects the smallest value and MAX() selects the This repository contains solutions to all the HackerRank SQL Practice Questions - HackerRank-SQL-Challenges-Solutions/Advanced Select/Occupations. Give a star For my work. Code The solutions of all SQL hackerrank challenges using MySQL . Each challenge has a Hacker rank SQL intermediate solution. d happens to equal the maximum value in Western Longitude SQL (Intermediate) SQL (Advanced) Difficulty. id GROUP BY CO. Paneer 4. Hackerrank. Find and fix vulnerabilities 58 SQL-Hackerrank challenge solutions for DB2, MySQL, Oracle, and MS SQL Server. product_name, Coalesce((ii. Retrieve top selling products. Advanced Select. For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S). inner join invoice on customer. HackerRank integrates with Oracle Recruiting Cloud for Tests and Interviews to facilitate an easy and seamless hiring experience. Product Actions. _____ SUBSCRIBE!Do you want to understand how to solve SQL Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company You signed in with another tab or window. Top. - adminazhar/-hackerrank-SQL-intermediate-skills-certification-test-solution The solutions of all the SQL challenges for all easy, medium and hard challenges on HackerRank executed on MySQL environment compiled. - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Sales Per City(Solution-1,2). The output column headers should be Doctor, Professor, Singer, I have sales data in BQ which contains following columns - Customer Id | ItemID | Order_Qty | Order_Date I want to create a sales rank table based on total quantity sold for an item. Oracle SQL specifically. Then you'll have a table with all the costs. quantity. Skills. line_total_price,2) from city. Publish Date - November 12th, 2022 | Last Modified - November 12th, 2022Here’s a quick an easy SQL Hackerrank solution for one of the last “aggregate” courses. invoice_id = i. Solutions Basic Select Challenges I've executed a SELECT statement to retrieve number of products sold in each orders but I don't know How I can retrieve only TOP 10 orders. Customer Id | ItemID | Order_Qty | Order_Date Top selling product by category - SQL. Thanks. 0 stars Watchers. Customer Stories Partners Open Source GitHub Sponsors. HACKER_ID, COUNT(c. Key Competencies: My solutions to SQL problems on HackerRank # SQL Problems Page: https://www. My current query Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; mysql, or sql-server or postgres or Oracle? – DhruvJoshi. CHALLENGE_ID) TOT_CH FROM CHALLENGES c GROUP BY HACKER_ID), cteDups AS (SELECT TOT_CH, COUNT(TOT_CH) AS DUPS FROM cteCount Product GitHub Copilot. Medium. 9 years ago + 63 comments. The following tables contain contest data: Hackers: The hacker_id is the id of the hacker, and name is the name of the This repository contains my solutions to the problems proposed at HackerRank. SELECT customer_ID, first_name, last_name, sum(hc_sales_total) as totalsales FROM ( SELECT c. 300 3. Contribute to KimTisott/HackerRank-Solutions development by creating an account on GitHub. com/in/abhishweta-gupta-96078b1b9/ SELECT category, CASE WHEN category = 'customer' THEN c. Updated Jun 23, 2020; TSQL; The solutions to all the SQL challenges on HackerRank executed on ORACLE environment . e. country_name, Ci. SQL (Basic) SQL Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. com/in/abhishweta-gupta-96078b1b9/ Solutions for all SQL challenges on HackerRank executed on MySQL and MS SQL Server. c happens to equal the maximum value in Northern Latitude (LAT_N in STATION). I learned SQL under Udacity Introduction to Data Science nanodegree program. SELECT a. quantity), 0) AS quantity FROM customer c LEFT JOIN invoice i on c. SQL-Product-Sales-per-City files for the HackerRank Beginner and Intermediate SQL Certification Solutions - Vaneeza-7/HackerRank-SQL-Certification-Solutions. The first query is different from the other two, logically. You signed in with another tab or window. Products. My solutions of all the SQL challenges for all easy, medium and hard challenges on HackerRank. Now, Now, the question is to find the product with highest number of sales. Find and fix vulnerabilities Customer Stories Partners Executive Insights Open Source GitHub Sponsors. The syntax is to use FLOOR(). The rows will be populated with data from the view if any sales available, if not the row will have 0 values. id = i. id=orders. HackerRank is a platform for competitive coding. SELECT count(*) /*count of transactions*/ FROM transactions WHERE /*Transactions in the last two months*/ transaction_date > DATEADD(mm, -2, GETDATE()) /*For customers that have had a sale today*/ customer_number in (SELECT customer_number Invoice ===== InvoiceID CustomerID InvoiceDate TransactionDate InvoiceTotal Customer ===== CustomerID CustomerName What I want is a listing of all invoices where there is more than one per customer. 0 | Permalink. You signed out in another tab or window. 2 watching Forks. Sep 16, 2024. - adminazhar/hackerrank-SQL-basic-skills-certification-test-solution linkedin channel link: https://www. Star 12. SQL (Basic) SQL I need help to build a ORACLE SQL query that can give me Sales by Item Name for each month. Contribute to Imtiaze/HackerRank_SQL_Solutions development by creating an account on GitHub. id THEN 'customer' WHEN p. Generalized Solution. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Link to SQL Code on GitHub: The goal of this project is to analyze data from a sales records database for scale model cars and extract information for decision-making. Readme Activity. Output the first name of the customer. Subdomains. SQL HackerRank Solutions This repository contains comprehensive solutions to all SQL challenges on HackerRank, designed to aid in your preparation and mastery of SQL. what you are looking for is called a division query. You just need to correlate by product_code and remove the group by clause from the You signed in with another tab or window. - adminazhar/hackerrank-SQL-basic-skills-certification-test-solution Watch all Easy Hackerrank SQL Problems solved in this video. sql at main · Pavith19/HackerRank-SQL-Challenges-Solutions Product GitHub Copilot. 7. 0 forks 🎆🎉 Important points about this Repository!!!!! 🎉🎆 . id=customer. Your second attempt that filters with a correlated subquery is almost there. SELECT first_name from customers WHERE first_name not in (select first_name from customers join orders on customers. Blog; Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. If you are using a different SQL Language (for example MySQL) you might have to adapt the solution a little This repository contains my solutions to various HackerRank certification challenges. The query should. Each solution is crafted to be efficient and clear, making this an excellent resource for anyone looking to strengthen their SQL skills. To arrive at " the most " we need a ranking so dense_rank() can ordered by the sum of quantity (descending) and a rank of 1 would equate to "the most sold" (note: equal 1st position is allowed by using You signed in with another tab or window. I tried below query and it worked for me. inner join customer on city. id LEFT JOIN product p ON Contribute to rifa8/SQL-Hackerrank-Solutions development by creating an account on GitHub. AccountNo = C. Host and manage packages Security. ; Advanced: Expert-level problems and more complex queries. Products without sales: Business Expansion: Write a query to find all pairs of customers and agents customer_table with customer_ID (key field), customer_name; orders_table with order_ID (key field), customer_ID, product_ID; Now suppose I would like to find the names of all the customers who have ordered more than 10 different types of product, and the number of types of products they ordered. SELECT c. MySQL solution-select (salary * months)as earnings ,count(*) from employee group by 1 order by earnings desc limit 1; 285 Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. I have a table "SELLS" with all sells of a shop and I want to display how many sales for each product each day of a period. Code Issues Pull requests All HackerRank solutions for Python, Java, SQL, C, C++, Algorithms, Data Structures. Input Format. exchange_rate) and calculates a row number for each row. - Sushanth72/SQL-HackeRank-Solutions View all solutions Resources Topics. I don't want to group or count the invoices, I actually need to see all invoices. 200 2. Crack your coding interview and CodeRankGPT helps you solve HackerRank coding problems during your coding interview. city_name,COUNT(city_id) AS cnt , AVG(COUNT(city_id)) OVER() avg_cnt FROM COUNTRY CO INNER JOIN City CI ON CI. Solutions for HackerRank challenges. sql & 2. Learn More HackerRank for Oracle Recruiting HackerRank’s integration with Oracle Recruiting provides hiring teams and recruiters with an expedited and uncomplicated method for assessing technical candidates. It is very important that you all first give it This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. SELECT codigo_orden AS ORDER_ID, COUNT(codigo_producto) Welcome to CarrY4U If you want to get the products that does not exists in orderline table you can simply use LEFT join with WHERE orderline. There are almost always multiple solutions to the same problem. Nerves can peak during the programming test, and even experienced developers might blank Logic: The only tricky thing here is “rounded down to the nearest integer”. The second query uses a redundant select distinct. Customer_spending. city_id = CI. For each row return customer name, product name, and the quantity of the In this post, we will be covering all the solutions to SQL on the HackerRank platform. This document walks through different use cases supported by the HackerRank—Oracle Recruiting Cloud (ORC) Integration and covers FAQs. Write better code with AI hackerrank solutions github | hackerrank all solutions | hackerrank solutions for java | hackerrank video tutorial | hackerrank cracking the coding interview solutions | hackerrank data structures | hackerrank solutions algorithms | hackerrank challenge | hackerrank coding challenge Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. I have taken HackerRank test on 22 July 2022. id AS product_id, invoice_item. id AS invoice_item_id, COALESCE(customer_name, 'N/A') customer_name, COALESCE(product_name, 'N/A') This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. The output would look something like this: Product GitHub Copilot. So, after reading some other materials and trying a few different things, I think I have a correct query. Unsolved. The certificate can be viewed here. Updated Mar 8, 2020; Aman9026 / HackerRank. Your three queries are different semantically, as written with the provided table definitions. first_Name, c. Basic Select. Id = P. Modified 9 years, (SQL Server, Oracle, PostgreSQL This is too long for a comment. Data Two tables: Customers and Orders. from CITY;-2 | Permalink. 0. id INNER JOIN Customer CU ON CU. SELECT p. customer_name, a. This repository contains all the solutions to the SQL questions listed in the Hackerrank platform , can be used by coders for reference purpose. ItemName = 'spoon' THEN 1 Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. id END AS 'id', CASE WHEN category = 'customer' THEN c. 1 month ago + 0 comments. CustomerName AS Customer, CASE WHEN COUNT(CASE WHEN i. Repo gathered by CodeRankGPT - Solve HackerRank coding problems during your coding interview, in real-time and undetectable 😎 Long ago Oracle introduced analytic functions for this kind of processing - to avoid joins, which may often be expensive (take a long time to process, compared to everything else in the query). Solve Challenge. 2 Questions are asked, as of now "City where each product has been sold" refers to the city of consumption, so you need to join transactions to consumers, sum the quantity by that city and the product. It is designed for experienced SQL professionals who want to validate their skills and advance their careers. Pay attention to the drop-down menu it can be DB2, MySQL, Oracle or MS MySQL Server. customerId = customers. My solution: WITH MaxScores AS ( SELECT Hacker_ID, Challenge_ID, MAX(Score) AS MaxScore FROM Submissions GROUP BY Hacker_ID, Challenge_ID ), SummedScores AS ( SELECT Hacker_ID, SUM(MaxScore) AS TotalScore FROM MaxScores GROUP BY Hacker_ID ) SELECT S. The Ultimate Guide to Mastering “CASE WHEN” in SQL for Data Wizards. It focuses solely on offering correct answers for SQL queries, joins, and aggregations, helping users pass the certification efficiently. Unless quantity is declared as NOT NULL, then it can return matching records where the quantity is NULL. Topics Customer Stories Partners Open Source GitHub Sponsors mysql sql oracle hackerrank mysql-database oracle-11g oracle-db oracle-12c oracle-database hackerrank SandraMoses / HackerRank-SQL-Challenges-Solutions Star 0. Click here to see more codes for NodeMCU ESP8266 and similar You want conditional aggregation: SELECT c. - sharathreddy31/SQL You signed in with another tab or window. Reload to refresh your session. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Skip to content HackerRank SQL Challenge Solutions . Multiple orders of the same product does not count. - LinconDash/Hackerrank-SQL-Solutions PL/SQL is an extension of the SQL language that combines the data manipulation power of SQL with the processing power of procedural language to create super-powerful SQL queries. - Ishika63/HackerRank-SQL-Intermediate-Solution Question Find customers who have never made an order. The actual question is all customers details even those without invoices and all products even those which are not sold. Find and fix vulnerabilities Codespaces. We then apply SUM() to calculate the linkedin channel link: https://www. You switched accounts on another tab or window. Star 59. srinath_deepika. the final value is appearing as 2251. I have data like below customer_id city timestamp amount 123 hyderbad currentdate 130 123 hyderbad currentdate 200 200 bangalore currentdate 300 300 bangalore currentdate 400 Customer_id can be multiple times I have written the following code for top 10 sales based on customer_id as below. Orders. Each solution includes a brief explanation of the problem and my approach to solving it. flag and sorting data Query all columns for every row in a table. 2 Questions are asked, as of now 2 questions will be asked from these questions, provided the solution also: Click here to see solutions for all Machine Learning Coursera Assignments. Establish a skills Saved searches Use saved searches to filter your results more quickly Problem. Contribute to phoenixSP/Hackerrank-sql development by creating an account on GitHub. id = c. Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test 🎓. Query the number of ocurrences of each occupation in OCCUPATIONS. Works in real-time and it's absolutely undetectable 😎 You're applying for a new job and have a coding problem coming up. " Learn more The solutions of all SQL challenges on HackerRank executed on either MySQL or MS SQL environment. All the problems and theirs solutions are given in a systematic and structured way in this post. customer_id. Aggregation. CASE WHEN This repository contains all solutions and "thought process" to Hackerrank's SQL challenges. You are viewing a single comment's thread. I also used Hackerrank to practice the queries i learned. The tables I'm using are: Customers. Please check 1. These are not the only solutions. ItemName = 'knife' THEN 1 END) > 0 THEN 'Y' ELSE 'N' END AS Knife, CASE WHEN COUNT(CASE WHEN i. ( dt, amt, src_curr, x_rate ) as ( select sales_date, sales_amount, currency, null from sales union all select effective_date, null Hackerrank sql solved using Oracle SQL. Instant dev environments GitHub Copilot. Hacker_ID, H. So, without wasting any time, let’s jump to the This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. Id AND R. HackerRank SQL Solutions 20 July 2020 While SQLPad takes a on helping data science and data analytics candidates for their SQL coding interviews from a business perspective. product_name, a. By detailing sales figures per city and identifying customers who spent 25% or less than You can use common table expressions to turn your repeated subqueries into inline views which you can query just as you would a normal view: WITH cteCount AS (SELECT c. I have a problem I can't find a solution. Name, S. Contains solutions of the sql queries of HackerRank You signed in with another tab or window. linkedin. id WHEN category = 'product' THEN p. You signed in with another tab or window. The strategy is based on a double negation, think: "give me all the customers for which there is no product, that has never been purchased" in SQL: Mount Blue is conducting a contest and the person who solves all the problems gets an opportunity for an entry level SDE developer role,and this repository for the storage and display of solutions to various problems of this contest on Hacker Rank. Generate the contest leaderboard. SQL-Business-Expansion and 2. We use cookies to ensure you have the best browsing experience on our website. ________ You signed in with another tab or window. They weren't the best, but Add this topic to your repo To associate your repository with the hackerrank-sql-solutions topic, visit your repo's landing page and select "manage topics. Hard. Find and fix vulnerabilities Exclude all hackers with a total score of 0 from your result. By detailing sales figures per city and identifying customers who spent 25% or less than the average, this solution aids in strategic Explore and run machine learning code with Kaggle Notebooks | Using data from Sales and Customer data Write a query that will return sales details of all customers and products. This is a new question Hackerrank has added for the advance level SQL certification. mysql data sql solutions hackerrank sql-query data-engineering mssql problem-solving hackerrank-solutions hackerrank-challenges sql-challenges mssql-server. com - alvesmog/hackerRank-solutions sql hackerrank hackerrank-solutions sql-history hackerrank-30dayschallange hackerrank-sql hackerrank-statistics hackerrank-sql-solutions hackerrank-solutions-github sql-hackerrank hackerrank-sql-challenge hackerrank-solution hackerrank-sql-solutions-oracle hackerrank-sql-certificate hackerrank-sql-solution hackerrank-sql-problems hackerrank-sql In this repository, you will find updated SQL solutions for all HackerRank problems as of 2024. Surprisingly it does seem to understand PL/SQL; and even more surprisingly it handles the set The repository is organized as follows: Easy: Beginner-level SQL challenges. id AS customer_id, product. country_name,CI. Advanced Join. Print " N / A " for a null customer or product name, and 0 for a null. 49%. - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Without Sales(solution-1,2). Certificate can be viewed Here. Updated Aug 24, 2022; HackerRankGPT / hackerrank-solutions. ; Consider P1(a,b) and P2(c,d)to be two points on a 2D plane. Submissions. 1 month You signed in with another tab or window. Quantity Sold I have the following SQL statement that shows the total sales amount for customers in cities who have done at least 2 orders. We use cookies to ensure you This repository contains MySQL solutions of the HackerRank SQL Intermediate Certificate problems which I encountered during the test. country_id = CO. Problem. Easy. This table contains Explanation: In this query, we use the YEAR() and MONTH() functions to extract the year and month from the Order_date column. 39. In neither of the solutions do you guarantee to generate the results with the correct ordering. Fund open source developers The ReadME Project hackerrank-solutions oracle-sql Resources. CEIL(): Return the smallest integer value that is greater than or equal UNION your two queries together. quantity FROM (SELECT customer. 50%. x), the exchange rate (e. Contains solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. Stars. Question 1: Which products Here is a solution for your problem: SELECT customers. customer_name, p. city_id. FirstName, P. This query joins the Sales and Products tables on the product_id column, groups the results by product name, and calculates the total sales revenue for each product. Key Features Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test 🎓. Explore my GitHub repository to learn from my experiences and find inspiration for your SQL learning path. Problem 1. Find and fix vulnerabilities Customer Stories Partners Executive the query would return customer 1 even though Customer 1 did not but all the products (namely, they did not buy product P_ID=2. Basic Join. 400 4. Here are the columns that are needed in query – Date (month), Item Name, Quantity Sold, Average Unit Price, Net Sales , Credit units. AccountNo ORDER BY Revenue DESC I'm trying to calculate the total purchase amount of each customer from the database available online on W3 Schools. Sign in Product Actions. This is appears to be a query that can be solved with relational division and one way to achieve that is by utilizing nested NOT EXISTS queries. name; Just add GROUP BY in your query in last to group count of invoices for SQL. : enclosed in parentheses). AI DevOps Security Software Development HackerRank-SQL(certification)-Product-Sales-Per-City. mysql. Manage You signed in with another tab or window. Hackerrank Solution You can toss a subquery in your WHERE clause to find customers that have had sales today:. ; Medium: Intermediate-level SQL challenges. Top Earners | Easy | HackerRank We define an employee's total earnings to be their monthly salary × months worked, and the maximum total earnings to be the maximum total earnings for any employee in the HackerRank + Oracle Recruiting Merging cutting-edge technology to evaluate technical candidates with state-of-the-art recruiting tools. yhyzyz buxzup knnnhs tbde aztjhg edmyrqn mcje moohg hgc yeaenjspi